🌟 [ 9 ] 1590. Make Sum Divisible by P | Daily Challenge | 3 Oct 2024 | Java [ @ ]
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Support me 🙌🏻: [ 🔗 Click here 🌐 ‼️ ] an array of positive integers nums, remove the smallest subarray (possibly empty) such that the sum of the remaining elements is divisible by p. It is not allowed to remove the whole array.
Return the length of the smallest subarray that you need to remove, or -1 if it's impossible.
A subarray is defined as a contiguous block of elements in the array.
CHAPTERS
0:00 Introduction
0:17 Question Explanation
1:57 Intuition
3:50 Brute Force Approach
6:21 Intuition for optimised approach
10:18 Example Walk Through
16:32 Live Coding
21:50 Example Walkthrough in code
27:12 Time & Space Complexity
27:38 Conclusion
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[ 9D ] 1590. Make Sum Divisible by P | Daily Challenge | 3 Oct 2024 | Java World [1]
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1590. Make Sum Divisible by P | Daily Challenge | 3 Oct 2024 | Java | POTD #dsa
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